What is the answer to (x+7)(x-3)=(x+1)^2 ?

The answer to (x+7)(x-3)=(x+1)^2 is x=11

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(x+7)(x-3)=(x+1)^2

(x + 7) (x - 3) = (x + 1)^{2}

x = 11

Solution steps

(x + 7) (x - 3) = (x + 1)^{2}

Expand

(x + 7) (x - 3) : x^{2} + 4 x - 21

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{2} + 4 x - 21 = x^{2} + 2 x + 1

Move

21

to the right side

x^{2} + 4 x = x^{2} + 2 x + 22

Subtract

x^{2} + 2 x

from both sides

x^{2} + 4 x - (x^{2} + 2 x) = x^{2} + 2 x + 22 - (x^{2} + 2 x)

Simplify

2 x = 22

Divide both sides by

2

x = 11

24 3^{\frac{6}{5}}

18 \cdot x^{2} - \frac{1}{2} \cdot x - \frac{5}{2} = 0

\frac{x - 1}{x ^{3} + 1} \geq 0

\frac{3 x - 1}{4} = \frac{2 x + 3}{3}

54

What is the answer to (x+7)(x-3)=(x+1)^2 ?
The answer to (x+7)(x-3)=(x+1)^2 is x=11
Solve for x: (x+7)(x-3)=(x+1)^2
The solution is x=11