What is expand (3x+4)(3x-4)(9x^2+16) ?

The solution to expand (3x+4)(3x-4)(9x^2+16) is 81x^4-256

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expand (3x+4)(3x-4)(9x^2+16)

expand

(3 x + 4) (3 x - 4) (9 x^{2} + 16)

81 x^{4} - 256

Solution steps

(3 x + 4) (3 x - 4) (9 x^{2} + 16)

Expand

(3 x + 4) (3 x - 4) (9 x^{2} + 16) : (9 x^{2} - 16) (9 x^{2} + 16)

= (9 x^{2} - 16) (9 x^{2} + 16)

Apply Difference of Two Squares

(9 x^{2} - 16) (9 x^{2} + 16) : 81 x^{4} - 256

= 81 x^{4} - 256

f (y) = - y

\frac{3}{10} (15)

(9) (2)

ln (0.35)

- 2 \cdot \frac{2}{5}

What is expand (3x+4)(3x-4)(9x^2+16) ?
The solution to expand (3x+4)(3x-4)(9x^2+16) is 81x^4-256