What is (x+1)(x+1)(x-1)(x-1) ?

The solution to (x+1)(x+1)(x-1)(x-1) is (x+1)^2(x-1)^2

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simplify (x+1)(x+1)(x-1)(x-1)

simplify

(x + 1) (x + 1) (x - 1) (x - 1)

(x + 1)^{2} (x - 1)^{2}

Solution steps

(x + 1) (x + 1) (x - 1) (x - 1)

Apply exponent rule:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x + 1)^{2} (x - 1) (x - 1)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x + 1)^{2} (x - 1)^{2}

3 \cdot 1 0^{- 10}

\frac{1}{3} - \frac{7}{8}

(x + 2) (x - 3) - (- 2 x + 1) (x - 5)

- \frac{1}{5} \cdot (- 2)

3 + 0

What is (x+1)(x+1)(x-1)(x-1) ?
The solution to (x+1)(x+1)(x-1)(x-1) is (x+1)^2(x-1)^2