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Popular >

simplify i^{20}i^{32}i^{19}

Solution

simplify

i^{20} \cdot i^{32} \cdot i^{19}

Solution

- i

Solution steps

i^{20} i^{32} i^{19}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

i^{20} i^{32} i^{19} = i^{20 + 32 + 19}

= i^{20 + 32 + 19}

Add the numbers:

20 + 32 + 19 = 71

= i^{71}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

i^{71} = i^{70} i

= i^{70} i

Simplify

i^{70} : (- 1)^{35}

= (- 1)^{35} i

Simplify

(- 1)^{35} i : - i

= - i

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Frequently Asked Questions (FAQ)

What is i^{20}*i^{32}*i^{19} ?
The solution to i^{20}*i^{32}*i^{19} is -i