What is (2*3y^{-2})^{-3} ?

The solution to (2*3y^{-2})^{-3} is (y^6)/(216)

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simplify (2*3y^{-2})^{-3}

simplify

(2 \cdot 3 y^{- 2})^{- 3}

\frac{y ^{6}}{216}

Solution steps

(2 \cdot 3 y^{- 2})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(2 \cdot 3 y^{- 2})^{- 3} = \frac{1}{( 2 \cdot 3 y ^{- 2} ) ^{3}}

= \frac{1}{( 2 \cdot 3 y ^{- 2} ) ^{3}}

Simplify

(2 \cdot 3 y^{- 2})^{3} : \frac{216}{y ^{6}}

= \frac{1}{\frac{216}{y ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{6}}{216}

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