What is factor 16p^4-81 ?

The solution to factor 16p^4-81 is (4p^2+9)(2p+3)(2p-3)

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factor 16p^4-81

factor

16 p^{4} - 81

(4 p^{2} + 9) (2 p + 3) (2 p - 3)

Solution steps

16 p^{4} - 81

Apply exponent rules

= (4 p^{2})^{2} - 9^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 p^{2})^{2} - 9^{2} = (4 p^{2} + 9) (4 p^{2} - 9)

= (4 p^{2} + 9) (4 p^{2} - 9)

Factor

4 p^{2} - 9 : (2 p + 3) (2 p - 3)

= (4 p^{2} + 9) (2 p + 3) (2 p - 3)

\frac{1}{2} + \frac{4}{11}

4 e^{\frac{- 5 πi}{6}}

(1)^{9}

- x + x - 5 - 1 + x

8^{3} \cdot 8^{6}

What is factor 16p^4-81 ?
The solution to factor 16p^4-81 is (4p^2+9)(2p+3)(2p-3)