What is [2x-3(x-1)]-[(3x+1)(-x+2)] ?

The solution to [2x-3(x-1)]-[(3x+1)(-x+2)] is 3x^2-6x+1

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simplify [2x-3(x-1)]-[(3x+1)(-x+2)]

simplify

[2 x - 3 (x - 1)] - [(3 x + 1) (- x + 2)]

3 x^{2} - 6 x + 1

Solution steps

(2 x - 3 (x - 1)) - ((3 x + 1) (- x + 2))

Simplify

(2 x - 3 (x - 1)) - ((3 x + 1) (- x + 2)) : 2 x - 3 (x - 1) - (3 x + 1) (- x + 2)

= 2 x - 3 (x - 1) - (3 x + 1) (- x + 2)

Expand

- 3 (x - 1) : - 3 x + 3

= 2 x - 3 x + 3 - (3 x + 1) (- x + 2)

Expand

- (3 x + 1) (- x + 2) : 3 x^{2} - 5 x - 2

= 2 x - 3 x + 3 + 3 x^{2} - 5 x - 2

Group like terms

= 3 x^{2} + 2 x - 3 x - 5 x + 3 - 2

Add similar elements:

2 x - 3 x - 5 x = - 6 x

= 3 x^{2} - 6 x + 3 - 2

Subtract the numbers:

3 - 2 = 1

= 3 x^{2} - 6 x + 1

x (x + 1) (x - 3)

\frac{- 3 - 9 i}{5 - 8 i}

x (x + 2 + 2)

7 (12.5) - 80

4 p^{7} q^{2} + p^{4} q^{2}

What is [2x-3(x-1)]-[(3x+1)(-x+2)] ?
The solution to [2x-3(x-1)]-[(3x+1)(-x+2)] is 3x^2-6x+1