What is factor x^4-x^2+2x-1 ?

The solution to factor x^4-x^2+2x-1 is (x^2+x-1)(x^2-x+1)

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factor x^4-x^2+2x-1

factor

x^{4} - x^{2} + 2 x - 1

(x^{2} + x - 1) (x^{2} - x + 1)

Solution steps

x^{4} - x^{2} + 2 x - 1

Factor

- x^{2} + 2 x - 1 : - (x - 1)^{2}

= x^{4} - (x - 1)^{2}

Simplify

x^{4} : (x^{2})^{2}

= (x^{2})^{2} - (x - 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2})^{2} - (x - 1)^{2} = (x^{2} + (x - 1)) (x^{2} - (x - 1))

= (x^{2} + (x - 1)) (x^{2} - (x - 1))

Simplify

(x^{2} + (x - 1)) (x^{2} - (x - 1)) : (x^{2} + x - 1) (x^{2} - x + 1)

= (x^{2} + x - 1) (x^{2} - x + 1)

\frac{4}{1} - \frac{3}{2}

22 \cdot 6

50 y^{50} - 32 z^{100}

25 x^{2 n} - \frac{1}{16}

0.0 4^{3}

What is factor x^4-x^2+2x-1 ?
The solution to factor x^4-x^2+2x-1 is (x^2+x-1)(x^2-x+1)