What is ((p^3)/(q^2))^{-3} ?

The solution to ((p^3)/(q^2))^{-3} is (q^6)/(p^9)

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simplify ((p^3)/(q^2))^{-3}

simplify

(\frac{p ^{3}}{q ^{2}})^{- 3}

\frac{q ^{6}}{p ^{9}}

Solution steps

(\frac{p ^{3}}{q ^{2}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{p ^{3}}{q ^{2}})^{- 3} = \frac{1}{( \frac{p ^{3}}{q ^{2}} ) ^{3}}

= \frac{1}{( \frac{p ^{3}}{q ^{2}} ) ^{3}}

Simplify

(\frac{p ^{3}}{q ^{2}})^{3} : \frac{p ^{9}}{q ^{6}}

= \frac{1}{\frac{p ^{9}}{q ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{q ^{6}}{p ^{9}}

(- 6 ab) (0.5 a c)

\frac{3 ^{- 4} + 5 ^{8}}{5 ^{- 4}}

3.2 \cdot 1 0^{3}

(3 x + 3 y)^{2}

\frac{1}{3} 128