What is sqrt(2^2+1^2+1^2) ?

The solution to sqrt(2^2+1^2+1^2) is square root of 6

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simplify sqrt(2^2+1^2+1^2)

simplify

2^{2} + 1^{2} + 1^{2}

6

Decimal Notation

2.44948 \dots

Solution steps

2^{2} + 1^{2} + 1^{2}

Add similar elements:

1^{2} + 1^{2} = 2 \cdot 1^{2}

= 2^{2} + 2 \cdot 1^{2}

2^{2} = 4

2 \cdot 1^{2} = 2

= 4 + 2

Add the numbers:

4 + 2 = 6

= 6

125 + 8 x^{3}

- - 29

29 - 316

- - 65

ln (2.9)

What is sqrt(2^2+1^2+1^2) ?
The solution to sqrt(2^2+1^2+1^2) is square root of 6