What are the solutions to the equation 1/6 t^2-4=0 ?

The solutions to the equation 1/6 t^2-4=0 are t=2sqrt(6),t=-2sqrt(6)

Find the zeros of 1/6 t^2-4=0

The zeros of 1/6 t^2-4=0 are t=2sqrt(6),t=-2sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{6} t^{2} - 4 = 0

t = 26, t = - 26

Decimal Notation

t = 4.89897 \dots, t = - 4.89897 \dots

Solution steps

\frac{1}{6} t^{2} - 4 = 0

Move

4

to the right side

\frac{1}{6} t^{2} = 4

Multiply both sides by

6

t^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 24, t = - 24

24 = 26

- 24 = - 26

t = 26, t = - 26

lo g_{8} (32)

\frac{1}{9} + \frac{1}{25}

\frac{3. 1 ^{2} - 9}{3.1 - 3}

9 x^{2} - 11 = 0

\frac{3 π}{4} \cdot \frac{180}{π}

What are the solutions to the equation 1/6 t^2-4=0 ?
The solutions to the equation 1/6 t^2-4=0 are t=2sqrt(6),t=-2sqrt(6)
Find the zeros of 1/6 t^2-4=0
The zeros of 1/6 t^2-4=0 are t=2sqrt(6),t=-2sqrt(6)