What is expand (2b+3c)(4b^2-6bc+9c^2) ?

The solution to expand (2b+3c)(4b^2-6bc+9c^2) is 8b^3+27c^3

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expand (2b+3c)(4b^2-6bc+9c^2)

expand

(2 b + 3 c) (4 b^{2} - 6 b c + 9 c^{2})

8 b^{3} + 27 c^{3}

Solution steps

(2 b + 3 c) (4 b^{2} - 6 b c + 9 c^{2})

Distribute parentheses

= 2 b \cdot 4 b^{2} + 2 b (- 6 b c) + 2 b \cdot 9 c^{2} + 3 c \cdot 4 b^{2} + 3 c (- 6 b c) + 3 c \cdot 9 c^{2}

Simplify

2 b \cdot 4 b^{2} + 2 b (- 6 b c) + 2 b \cdot 9 c^{2} + 3 c \cdot 4 b^{2} + 3 c (- 6 b c) + 3 c \cdot 9 c^{2} : 8 b^{3} + 27 c^{3}

= 8 b^{3} + 27 c^{3}

3 (- x)^{2} + 4 (- x) - 2

1090

(8 - 2) a + 9 b - (3 + 2) a + 10

(\frac{1}{6})^{2}

∣ 6 - 11 + 3 ∣

What is expand (2b+3c)(4b^2-6bc+9c^2) ?
The solution to expand (2b+3c)(4b^2-6bc+9c^2) is 8b^3+27c^3