What is factor 27+64q^3 ?

The solution to factor 27+64q^3 is (4q+3)(16q^2-12q+9)

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factor 27+64q^3

factor

27 + 64 q^{3}

(4 q + 3) (16 q^{2} - 12 q + 9)

Solution steps

27 + 64 q^{3}

Write in the standard form

= 64 q^{3} + 27

Apply exponent rules

= (4 q)^{3} + 3^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(4 q)^{3} + 3^{3} = (4 q + 3) (4^{2} q^{2} - 3 \cdot 4 q + 3^{2})

= (4 q + 3) (4^{2} q^{2} - 3 \cdot 4 q + 3^{2})

Simplify

(4 q + 3) (4^{2} q^{2} - 3 \cdot 4 q + 3^{2}) : (4 q + 3) (16 q^{2} - 12 q + 9)

= (4 q + 3) (16 q^{2} - 12 q + 9)

3^{2} - 16

\frac{15}{10} \cdot \frac{3}{4}

- (3.7 u - 5 v + 0.4)

∣ 1 - 11 ∣

(2^{4} 10)^{2}

What is factor 27+64q^3 ?
The solution to factor 27+64q^3 is (4q+3)(16q^2-12q+9)