What is 1/(\sqrt[4]{x^2-8x)} ?

The solution to 1/(\sqrt[4]{x^2-8x)} is ((x^2-8x)^{3/4})/(x^2-8x)

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simplify 1/(\sqrt[4]{x^2-8x)}

simplify

\frac{( x ^{2} - 8 x ) ^{\frac{3}{4}}}{x ^{2} - 8 x}

Solution steps

Multiply by the conjugate

\frac{( x ^{2} - 8 x ) ^{\frac{3}{4}}}{( x ^{2} - 8 x ) ^{\frac{3}{4}}}

1 \cdot (x^{2} - 8 x)^{\frac{3}{4}} = (x^{2} - 8 x)^{\frac{3}{4}}

= \frac{( x ^{2} - 8 x ) ^{\frac{3}{4}}}{x ^{2} - 8 x}

y^{2} + 24 y + 144

4 (x - 3) + 2 x (x - 3)

\frac{3 + 9 i}{- 6 - 6 i}

738.1 (1.065)^{13}

\frac{80}{32}

What is 1/(\sqrt[4]{x^2-8x)} ?
The solution to 1/(\sqrt[4]{x^2-8x)} is ((x^2-8x)^{3/4})/(x^2-8x)