What is (6x^2-x-4)+(2x^2+5x-5) ?

The solution to (6x^2-x-4)+(2x^2+5x-5) is 8x^2+4x-9

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simplify (6x^2-x-4)+(2x^2+5x-5)

simplify

(6 x^{2} - x - 4) + (2 x^{2} + 5 x - 5)

8 x^{2} + 4 x - 9

Solution steps

(6 x^{2} - x - 4) + (2 x^{2} + 5 x - 5)

Simplify

(6 x^{2} - x - 4) + (2 x^{2} + 5 x - 5) : 6 x^{2} - x - 4 + 2 x^{2} + 5 x - 5

= 6 x^{2} - x - 4 + 2 x^{2} + 5 x - 5

Group like terms

= 6 x^{2} + 2 x^{2} - x + 5 x - 4 - 5

Add similar elements:

6 x^{2} + 2 x^{2} = 8 x^{2}

= 8 x^{2} - x + 5 x - 4 - 5

Add similar elements:

- x + 5 x = 4 x

= 8 x^{2} + 4 x - 4 - 5

Subtract the numbers:

- 4 - 5 = - 9

= 8 x^{2} + 4 x - 9

15 \cdot 14 \cdot 13

- 12 x^{2} - 9 x

- 6 x - 2

- 6 x - 7

5 \cdot (- \frac{1}{3})

What is (6x^2-x-4)+(2x^2+5x-5) ?
The solution to (6x^2-x-4)+(2x^2+5x-5) is 8x^2+4x-9