What is (x^{-2}xy^7y^{-4})/1 ?

The solution to (x^{-2}xy^7y^{-4})/1 is (y^3)/x

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simplify (x^{-2}xy^7y^{-4})/1

simplify

\frac{x ^{- 2} x y ^{7} y ^{- 4}}{1}

\frac{y ^{3}}{x}

Solution steps

\frac{x ^{- 2} x y ^{7} y ^{- 4}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= x^{- 2} x y^{7} y^{- 4}

Simplify

x^{- 2} x y^{7} y^{- 4} : \frac{y ^{3}}{x}

= \frac{y ^{3}}{x}

\frac{3}{4} \div 7

x 54 x^{2} y^{3}

\frac{72}{27}

\frac{2}{x - 1} + \frac{1}{x}

(3^{2 x} + 3^{4 x})^{2}