What are the solutions to the equation 6x^2+6x+7=0 ?

The solutions to the equation 6x^2+6x+7=0 are x=-1/2+i(sqrt(33))/6 ,x=-1/2-i(sqrt(33))/6

Find the zeros of 6x^2+6x+7=0

The zeros of 6x^2+6x+7=0 are x=-1/2+i(sqrt(33))/6 ,x=-1/2-i(sqrt(33))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 6 x + 7 = 0

x = - \frac{1}{2} + i \frac{33}{6}, x = - \frac{1}{2} - i \frac{33}{6}

Solution steps

6 x^{2} + 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

Simplify

6^{2} - 4 \cdot 6 \cdot 7 : 233 i

x_{1, 2} = \frac{- 6 \pm 2 33 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 2 33 i}{2 \cdot 6}, x_{2} = \frac{- 6 - 2 33 i}{2 \cdot 6}

x = \frac{- 6 + 2 33 i}{2 \cdot 6} : - \frac{1}{2} + i \frac{33}{6}

x = \frac{- 6 - 2 33 i}{2 \cdot 6} : - \frac{1}{2} - i \frac{33}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{33}{6}, x = - \frac{1}{2} - i \frac{33}{6}

x^{3} \cdot x^{\frac{1}{2}}

1 - \frac{2}{x} > 3 x

\frac{2 + 3 i}{4 + i}

- 7 k \leq - 84

5 > - 6 - 2 x

What are the solutions to the equation 6x^2+6x+7=0 ?
The solutions to the equation 6x^2+6x+7=0 are x=-1/2+i(sqrt(33))/6 ,x=-1/2-i(sqrt(33))/6
Find the zeros of 6x^2+6x+7=0
The zeros of 6x^2+6x+7=0 are x=-1/2+i(sqrt(33))/6 ,x=-1/2-i(sqrt(33))/6