What is (4x^3-6x^2+8x)/(2x) ?

The solution to (4x^3-6x^2+8x)/(2x) is 2x^2-3x+4

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simplify (4x^3-6x^2+8x)/(2x)

simplify

\frac{4 x ^{3} - 6 x ^{2} + 8 x}{2 x}

2 x^{2} - 3 x + 4

Solution steps

\frac{4 x ^{3} - 6 x ^{2} + 8 x}{2 x}

Factor

4 x^{3} - 6 x^{2} + 8 x : 2 x (2 x^{2} - 3 x + 4)

= \frac{2 x ( 2 x ^{2} - 3 x + 4 )}{2 x}

Cancel the common factor:

2

= \frac{x ( 2 x ^{2} - 3 x + 4 )}{x}

Cancel the common factor:

x

= 2 x^{2} - 3 x + 4

3 x \cdot 2 x

(\frac{x}{2}) (\frac{x}{2})

\frac{5}{2} \div 4

- 3 + (- 14)

\frac{3}{8} + \frac{4}{7}