What is expand (x+4)(x+1)(2x-3)(x-1) ?

The solution to expand (x+4)(x+1)(2x-3)(x-1) is 2x^4+5x^3-14x^2-5x+12

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expand (x+4)(x+1)(2x-3)(x-1)

expand

(x + 4) (x + 1) (2 x - 3) (x - 1)

2 x^{4} + 5 x^{3} - 14 x^{2} - 5 x + 12

Solution steps

(x + 4) (x + 1) (2 x - 3) (x - 1)

Expand

(x + 4) (x + 1) (2 x - 3) (x - 1) : (x + 4) (x^{2} - 1) (2 x - 3)

= (x + 4) (x^{2} - 1) (2 x - 3)

Apply FOIL method

(x + 4) (x^{2} - 1) : x^{3} - x + 4 x^{2} - 4

= (x^{3} - x + 4 x^{2} - 4) (2 x - 3)

Distribute parentheses

= x^{3} \cdot 2 x + x^{3} (- 3) - x \cdot 2 x - x (- 3) + 4 x^{2} \cdot 2 x + 4 x^{2} (- 3) - 4 \cdot 2 x - 4 (- 3)

Simplify

x^{3} \cdot 2 x + x^{3} (- 3) - x \cdot 2 x - x (- 3) + 4 x^{2} \cdot 2 x + 4 x^{2} (- 3) - 4 \cdot 2 x - 4 (- 3) : 2 x^{4} + 5 x^{3} - 14 x^{2} - 5 x + 12

= 2 x^{4} + 5 x^{3} - 14 x^{2} - 5 x + 12

20 x^{2} - 45

\frac{1}{1 + 2 i} + \frac{1}{1 + 5 i}

- \frac{104}{48}

\frac{5}{9} - \frac{3}{9}

5 (2 a)^{2} - (2 a) + 3

What is expand (x+4)(x+1)(2x-3)(x-1) ?
The solution to expand (x+4)(x+1)(2x-3)(x-1) is 2x^4+5x^3-14x^2-5x+12