What is the answer to 7(x-3)+(x-1)(x+1)=x^{(2)}-5(x+2) ?

The answer to 7(x-3)+(x-1)(x+1)=x^{(2)}-5(x+2) is x=1

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7(x-3)+(x-1)(x+1)=x^{(2)}-5(x+2)

7 (x - 3) + (x - 1) (x + 1) = x^{(2)} - 5 (x + 2)

x = 1

Solution steps

7 (x - 3) + (x - 1) (x + 1) = x^{(2)} - 5 (x + 2)

7 (x - 3) + (x - 1) (x + 1) = x^{2} - 5 (x + 2)

Expand

- 5 (x + 2) : - 5 x - 10

x^{2} + 7 x - 22 = x^{2} - 5 x - 10

Expand

7 (x - 3) + (x - 1) (x + 1) : x^{2} + 7 x - 22

x^{2} + 7 x - 22 = x^{2} - 5 x - 10

Move

22

to the right side

x^{2} + 7 x = x^{2} - 5 x + 12

Subtract

x^{2} - 5 x

from both sides

x^{2} + 7 x - (x^{2} - 5 x) = x^{2} - 5 x + 12 - (x^{2} - 5 x)

Simplify

12 x = 12

Divide both sides by

12

x = 1

\frac{x}{3} < 2

3 \cdot \frac{5}{2}

\frac{1}{\frac{7}{25}}

(x^{4})^{- \frac{1}{2}}

(3 y^{3})^{4}

What is the answer to 7(x-3)+(x-1)(x+1)=x^{(2)}-5(x+2) ?
The answer to 7(x-3)+(x-1)(x+1)=x^{(2)}-5(x+2) is x=1
Solve for x: 7(x-3)+(x-1)(x+1)=x^{(2)}-5(x+2)
The solution is x=1