What is factor 1-8x^2-9x^4 ?

The solution to factor 1-8x^2-9x^4 is -(3x+1)(3x-1)(x^2+1)

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factor 1-8x^2-9x^4

factor

1 - 8 x^{2} - 9 x^{4}

- (3 x + 1) (3 x - 1) (x^{2} + 1)

Solution steps

1 - 8 x^{2} - 9 x^{4}

Write in the standard form

= - 9 x^{4} - 8 x^{2} + 1

Factor out

- 1 : - (9 x^{4} + 8 x^{2} - 1)

= - (9 x^{4} + 8 x^{2} - 1)

Factor

9 x^{4} + 8 x^{2} - 1 : (3 x + 1) (3 x - 1) (x^{2} + 1)

= - (3 x + 1) (3 x - 1) (x^{2} + 1)

x - 3 (x^{2} - x) + 5 x + x^{2}

9 \frac{1}{4} - 4 \frac{3}{4}

16 \cdot (- 7)

\frac{2 5}{6}

2 u^{2} v^{2} - 11 u v^{3} + 15 v^{4}

What is factor 1-8x^2-9x^4 ?
The solution to factor 1-8x^2-9x^4 is -(3x+1)(3x-1)(x^2+1)