What are the solutions to the equation x^2=4-x ?

The solutions to the equation x^2=4-x are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2

Find the zeros of x^2=4-x

The zeros of x^2=4-x are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2

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x^{2} = 4 - x

x = \frac{- 1 + 17}{2}, x = \frac{- 1 - 17}{2}

Decimal

x = 1.56155 \dots, x = - 2.56155 \dots

Solution steps

x^{2} = 4 - x

Move

x

to the left side

x^{2} + x = 4

Move

4

to the left side

x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 4) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 1}, x_{2} = \frac{- 1 - 17}{2 \cdot 1}

x = \frac{- 1 + 17}{2 \cdot 1} : \frac{- 1 + 17}{2}

x = \frac{- 1 - 17}{2 \cdot 1} : \frac{- 1 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{2}, x = \frac{- 1 - 17}{2}

- 70

4^{5}

x^{2} = 336

m^{2} + 24 m - 25

113 - 1133

What are the solutions to the equation x^2=4-x ?
The solutions to the equation x^2=4-x are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2
Find the zeros of x^2=4-x
The zeros of x^2=4-x are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2