What is ((1+i)^{62})/((-1-i)^{15)} ?

The solution to ((1+i)^{62})/((-1-i)^{15)} is -(1+i)^{47}

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simplify ((1+i)^{62})/((-1-i)^{15)}

simplify

\frac{( 1 + i ) ^{62}}{( - 1 - i ) ^{15}}

- (1 + i)^{47}

Solution steps

\frac{( 1 + i ) ^{62}}{( - 1 - i ) ^{15}}

(- 1 - i)^{15} = - (1 + i)^{15}

= \frac{( 1 + i ) ^{62}}{- ( 1 + i ) ^{15}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(1 + i)^{62} = (1 + i)^{15} (1 + i)^{47}

= \frac{( 1 + i ) ^{15} ( 1 + i ) ^{47}}{- ( 1 + i ) ^{15}}

Cancel the common factor:

(1 + i)^{15}

= \frac{( 1 + i ) ^{47}}{- 1}

Apply the fraction rule:

\frac{a}{- 1} = - a

= - (1 + i)^{47}

\frac{5 h}{h}

- 4 x^{4} + 24 x

\frac{1}{2} x + 3 x

2 a + 6 a + 5 b - 3 b

\frac{x ^{3}}{5} - 10 - x

What is ((1+i)^{62})/((-1-i)^{15)} ?
The solution to ((1+i)^{62})/((-1-i)^{15)} is -(1+i)^{47}