What is (\frac{x+9)/(x+3)-2}{x-3} ?

The solution to (\frac{x+9)/(x+3)-2}{x-3} is -1/(x+3)

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simplify (\frac{x+9)/(x+3)-2}{x-3}

simplify

\frac{\frac{x + 9}{x + 3} - 2}{x - 3}

- \frac{1}{x + 3}

Solution steps

\frac{\frac{x + 9}{x + 3} - 2}{x - 3}

Join

\frac{x + 9}{x + 3} - 2 : \frac{- x + 3}{x + 3}

= \frac{\frac{- x + 3}{x + 3}}{x - 3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{- x + 3}{( x + 3 ) ( x - 3 )}

Cancel

\frac{- x + 3}{( x + 3 ) ( x - 3 )} : - \frac{1}{x + 3}

= - \frac{1}{x + 3}

80 v^{2} u - 8 v^{3} + 40 v^{3}

(x - 3)^{2} - 9

(a^{2} - b^{2}) - (a - b)^{2}

3 y^{2} \cdot (- 2 y^{3}) + 4 y^{5}

\frac{91}{13}

What is (\frac{x+9)/(x+3)-2}{x-3} ?
The solution to (\frac{x+9)/(x+3)-2}{x-3} is -1/(x+3)