What is factor 4w^2-20w+25 ?

The solution to factor 4w^2-20w+25 is (2w-5)^2

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factor 4w^2-20w+25

factor

4 w^{2} - 20 w + 25

(2 w - 5)^{2}

Solution steps

4 w^{2} - 20 w + 25

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 w^{2} = (2 w)^{2}

25 = 5^{2}

- 20 w = - 2 \cdot 2 w \cdot 5

= (2 w)^{2} - 2 \cdot 2 w \cdot 5 + 5^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 w)^{2} - 2 \cdot 2 w \cdot 5 + 5^{2} = (2 w - 5)^{2}

= (2 w - 5)^{2}

\frac{16 x ^{2} - 81}{x ^{2} - 36} \leq 0

16 r^{2} + 10 = 0

lo g_{5} (\frac{1}{3125})

c = 180 (4) + 250

49 a^{2} - 169