What is (ab-2a)/(b^3-8) ?

The solution to (ab-2a)/(b^3-8) is a/(b^2+2b+4)

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simplify (ab-2a)/(b^3-8)

simplify

\frac{ab - 2 a}{b ^{3} - 8}

\frac{a}{b ^{2} + 2 b + 4}

Solution steps

\frac{ab - 2 a}{b ^{3} - 8}

Factor out common term

a

= \frac{a ( b - 2 )}{b ^{3} - 8}

Factor

b^{3} - 8 : (b - 2) (b^{2} + 2 b + 4)

= \frac{a ( b - 2 )}{( b - 2 ) ( b ^{2} + 2 b + 4 )}

Cancel the common factor:

b - 2

= \frac{a}{b ^{2} + 2 b + 4}

- \frac{1}{2} \cdot \frac{10}{9}

\frac{2}{\frac{2}{2}}

- (3 u + 8.2)

(4 + i) (- 2 - i)

(2 i) (- 2 + 3 i) (2 + 3 i)