What is expand (8x-4)(4x^2-3x+2) ?

The solution to expand (8x-4)(4x^2-3x+2) is 32x^3-40x^2+28x-8

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expand (8x-4)(4x^2-3x+2)

expand

(8 x - 4) (4 x^{2} - 3 x + 2)

32 x^{3} - 40 x^{2} + 28 x - 8

Solution steps

(8 x - 4) (4 x^{2} - 3 x + 2)

Distribute parentheses

= 8 x \cdot 4 x^{2} + 8 x (- 3 x) + 8 x \cdot 2 - 4 \cdot 4 x^{2} - 4 (- 3 x) - 4 \cdot 2

Simplify

8 x \cdot 4 x^{2} + 8 x (- 3 x) + 8 x \cdot 2 - 4 \cdot 4 x^{2} - 4 (- 3 x) - 4 \cdot 2 : 32 x^{3} - 40 x^{2} + 28 x - 8

= 32 x^{3} - 40 x^{2} + 28 x - 8

410 - 6 + 310

- (x - 5)

(- \frac{5}{2})^{4} - 2^{- 4}

1 5^{7}

- 2 \cdot (- \frac{3}{2})

What is expand (8x-4)(4x^2-3x+2) ?
The solution to expand (8x-4)(4x^2-3x+2) is 32x^3-40x^2+28x-8