What is [cos(A)+1][cos(A)-1] ?

The solution to [cos(A)+1][cos(A)-1] is -sin^2(A)

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simplify [cos(A)+1][cos(A)-1]

simplify

[cos (A) + 1] [cos (A) - 1]

- sin^{2} (A)

Solution steps

(cos (A) + 1) (cos (A) - 1)

Expand

(- 1 + cos (A)) (1 + cos (A)) : cos^{2} (A) - 1

= - 1 + cos^{2} (A)

Rewrite using trig identities

= - sin^{2} (A)

i^{6} - 5

0.4 (5 y + 6 z) + 7 z - 0.1 (8 z + 10 y)

\frac{6}{7} \cdot \frac{1}{10}

(- 6) \cdot (- 4)

(a^{\frac{1}{4}})^{4}

What is [cos(A)+1][cos(A)-1] ?
The solution to [cos(A)+1][cos(A)-1] is -sin^2(A)