What is the answer to x^2-5=(x-3)(x-2) ?

The answer to x^2-5=(x-3)(x-2) is x= 11/5

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x^2-5=(x-3)(x-2)

x^{2} - 5 = (x - 3) (x - 2)

x = \frac{11}{5}

Decimal Notation

x = 2.2

Solution steps

x^{2} - 5 = (x - 3) (x - 2)

Expand

(x - 3) (x - 2) : x^{2} - 5 x + 6

x^{2} - 5 = x^{2} - 5 x + 6

Move

5

to the right side

x^{2} = x^{2} - 5 x + 11

Subtract

x^{2} - 5 x

from both sides

x^{2} - (x^{2} - 5 x) = x^{2} - 5 x + 11 - (x^{2} - 5 x)

Simplify

5 x = 11

Divide both sides by

5

x = \frac{11}{5}

\frac{( x - 4 ) ( x + 2 )}{( x - 5 ) ( x + 8 )} \geq 0

(3 + 2 i)^{2}

36 a^{2} + 84 a + 49

5 x^{2} - 180 = 0

7 (5 x - 2) = 6 (6 x - 1)

What is the answer to x^2-5=(x-3)(x-2) ?
The answer to x^2-5=(x-3)(x-2) is x= 11/5
Solve for x: x^2-5=(x-3)(x-2)
The solution is x= 11/5