What is \sqrt[5]{-32}-\sqrt[3]{-27} ?

The solution to \sqrt[5]{-32}-\sqrt[3]{-27} is 1

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simplify \sqrt[5]{-32}-\sqrt[3]{-27}

simplify

1

Solution steps

= - 2 - (- 3)

Apply rule:

a - (- b) = a + b

- 2 - (- 3) = - 2 + 3

= - 2 + 3

Add the numbers:

- 2 + 3 = 1

= 1

36 x + 63

x + (x + 2)

m^{3} + \frac{4}{m ^{- 3}}

(x + 4)^{2} - 2 (x + 4) + 7

(x + i y)^{2} + (x - i y)^{2}

What is \sqrt[5]{-32}-\sqrt[3]{-27} ?
The solution to \sqrt[5]{-32}-\sqrt[3]{-27} is 1