What are the solutions to the equation x^2+0.5x+4=0 ?

The solutions to the equation x^2+0.5x+4=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4

Find the zeros of x^2+0.5x+4=0

The zeros of x^2+0.5x+4=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4

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x^{2} + 0.5 x + 4 = 0

x = - \frac{1}{4} + i \frac{3 7}{4}, x = - \frac{1}{4} - i \frac{3 7}{4}

Solution steps

x^{2} + 0.5 x + 4 = 0

Multiply both sides by

10

10 x^{2} + 5 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 10 \cdot 40}{2 \cdot 10}

Simplify

5^{2} - 4 \cdot 10 \cdot 40 : 157 i

x_{1, 2} = \frac{- 5 \pm 15 7 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 5 + 15 7 i}{2 \cdot 10}, x_{2} = \frac{- 5 - 15 7 i}{2 \cdot 10}

x = \frac{- 5 + 15 7 i}{2 \cdot 10} : - \frac{1}{4} + i \frac{3 7}{4}

x = \frac{- 5 - 15 7 i}{2 \cdot 10} : - \frac{1}{4} - i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{3 7}{4}, x = - \frac{1}{4} - i \frac{3 7}{4}

5 \cdot \frac{4}{3}

- \frac{2}{3} x + \frac{1}{3} + x = \frac{2}{5}

6 t \leq 7 t - 8

0 (x) = 5 x^{2} - 3 x + 7

4 x^{2} = 9 x - 3

What are the solutions to the equation x^2+0.5x+4=0 ?
The solutions to the equation x^2+0.5x+4=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4
Find the zeros of x^2+0.5x+4=0
The zeros of x^2+0.5x+4=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4