What is 5(x+1)-2(x^2-4x+5) ?

The solution to 5(x+1)-2(x^2-4x+5) is -2x^2+13x-5

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simplify 5(x+1)-2(x^2-4x+5)

simplify

5 (x + 1) - 2 (x^{2} - 4 x + 5)

- 2 x^{2} + 13 x - 5

Solution steps

5 (x + 1) - 2 (x^{2} - 4 x + 5)

Expand

5 (x + 1) : 5 x + 5

= 5 x + 5 - 2 (x^{2} - 4 x + 5)

Expand

- 2 (x^{2} - 4 x + 5) : - 2 x^{2} + 8 x - 10

= 5 x + 5 - 2 x^{2} + 8 x - 10

Group like terms

= - 2 x^{2} + 5 x + 8 x + 5 - 10

Add similar elements:

5 x + 8 x = 13 x

= - 2 x^{2} + 13 x + 5 - 10

Subtract the numbers:

5 - 10 = - 5

= - 2 x^{2} + 13 x - 5

sec^{2} (x) \cdot sec^{2} (x)

3 x + 5 - 4 x^{2} - 2 - x^{2} - 3 x + 1

- \frac{1}{2} \cdot \frac{5}{7}

e^{l n (x - 3)} + 3

1 \cdot 2^{14}