What are the solutions to the equation x^2-10x+25=0 ?

The solutions to the equation x^2-10x+25=0 are x=5

Find the zeros of x^2-10x+25=0

The zeros of x^2-10x+25=0 are x=5

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x^{2} - 10 x + 25 = 0

x = 5

Solution steps

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

(x + 2)^{2} - 64

2 x^{2} + 8 x + 9 = 0

5 (x - 8)^{2} + 10 = 15

8 x^{4} + 12 x^{2} - 20 x

0 = x + 19

What are the solutions to the equation x^2-10x+25=0 ?
The solutions to the equation x^2-10x+25=0 are x=5
Find the zeros of x^2-10x+25=0
The zeros of x^2-10x+25=0 are x=5