What is factor 25x^2y^2+20xy+4 ?

The solution to factor 25x^2y^2+20xy+4 is (5xy+2)^2

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factor 25x^2y^2+20xy+4

factor

25 x^{2} y^{2} + 20 x y + 4

(5 x y + 2)^{2}

Solution steps

25 x^{2} y^{2} + 20 x y + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 x^{2} y^{2} = (5 x y)^{2}

4 = 2^{2}

20 x y = 2 \cdot 5 x y \cdot 2

= (5 x y)^{2} + 2 \cdot 5 x y \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(5 x y)^{2} + 2 \cdot 5 x y \cdot 2 + 2^{2} = (5 x y + 2)^{2}

= (5 x y + 2)^{2}

b^{4} \cdot b^{3}

4^{2} + 1 2^{2}

5.4 \cdot 1 0^{3}

\frac{160}{9}

\frac{2}{3} x - 2

What is factor 25x^2y^2+20xy+4 ?
The solution to factor 25x^2y^2+20xy+4 is (5xy+2)^2