What is expand (x^3-8)(x^3+8) ?

The solution to expand (x^3-8)(x^3+8) is x^6-64

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expand (x^3-8)(x^3+8)

expand

(x^{3} - 8) (x^{3} + 8)

x^{6} - 64

Solution steps

(x^{3} - 8) (x^{3} + 8)

Apply Difference of Two Squares

(x^{3} - 8) (x^{3} + 8) : x^{6} - 64

= x^{6} - 64

2 (5 x - 1) + 14 x

8 y - [2 y^{2} - (3 y - 8)]

46 \cdot 2

12 x^{2} - 12 x

- 6 (x + 2)^{2} + 7