What is factor 8x^4-4x^3+12x^2 ?

The solution to factor 8x^4-4x^3+12x^2 is 4x^2(2x^2-x+3)

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factor 8x^4-4x^3+12x^2

factor

8 x^{4} - 4 x^{3} + 12 x^{2}

4 x^{2} (2 x^{2} - x + 3)

Solution steps

8 x^{4} - 4 x^{3} + 12 x^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} = x x^{2}

= 8 x^{2} x^{2} - 4 x x^{2} + 12 x^{2}

Rewrite

8

4 \cdot 2

Rewrite

12

4 \cdot 3

= 4 \cdot 2 x^{2} x^{2} - 4 x x^{2} + 4 \cdot 3 x^{2}

Factor out common term

4 x^{2}

= 4 x^{2} (2 x^{2} - x + 3)

- \frac{1}{2} + \frac{3}{7}

3 + \frac{3}{3}

\frac{1}{( - 4.5 ) ^{2} - 16}

\frac{1}{( - 4.5 ) ^{2} - 25}

a^{3} - a^{2} b - 7 a^{2} b + 9 a b^{2}

What is factor 8x^4-4x^3+12x^2 ?
The solution to factor 8x^4-4x^3+12x^2 is 4x^2(2x^2-x+3)