What are the solutions to the equation -5x^2+25x+1=0 ?

The solutions to the equation -5x^2+25x+1=0 are x=-(-25+sqrt(645))/(10),x=(25+sqrt(645))/(10)

Find the zeros of -5x^2+25x+1=0

The zeros of -5x^2+25x+1=0 are x=-(-25+sqrt(645))/(10),x=(25+sqrt(645))/(10)

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- 5 x^{2} + 25 x + 1 = 0

x = - \frac{- 25 + 645}{10}, x = \frac{25 + 645}{10}

Decimal Notation

x = - 0.03968 \dots, x = 5.03968 \dots

Solution steps

- 5 x^{2} + 25 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 ( - 5 ) \cdot 1}{2 ( - 5 )}

2 5^{2} - 4 (- 5) \cdot 1 = 645

x_{1, 2} = \frac{- 25 \pm 645}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 25 + 645}{2 ( - 5 )}, x_{2} = \frac{- 25 - 645}{2 ( - 5 )}

x = \frac{- 25 + 645}{2 ( - 5 )} : - \frac{- 25 + 645}{10}

x = \frac{- 25 - 645}{2 ( - 5 )} : \frac{25 + 645}{10}

The solutions to the quadratic equation are:

x = - \frac{- 25 + 645}{10}, x = \frac{25 + 645}{10}

r^{2} - 3 r + 4 = 0

z^{2} + 4 z = 2

- n + 2 - n < - \frac{2}{3} (9 n - 63)

5 x^{2} - 2 x + 3 = 0

500 x^{3} + 108 y^{18}

What are the solutions to the equation -5x^2+25x+1=0 ?
The solutions to the equation -5x^2+25x+1=0 are x=-(-25+sqrt(645))/(10),x=(25+sqrt(645))/(10)
Find the zeros of -5x^2+25x+1=0
The zeros of -5x^2+25x+1=0 are x=-(-25+sqrt(645))/(10),x=(25+sqrt(645))/(10)