What is factor 49a^8+28a^4b^2+4b^4 ?

The solution to factor 49a^8+28a^4b^2+4b^4 is (7a^4+2b^2)^2

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factor 49a^8+28a^4b^2+4b^4

factor

49 a^{8} + 28 a^{4} b^{2} + 4 b^{4}

(7 a^{4} + 2 b^{2})^{2}

Solution steps

49 a^{8} + 28 a^{4} b^{2} + 4 b^{4}

Break the expression into groups

= (49 a^{8} + 14 a^{4} b^{2}) + (14 a^{4} b^{2} + 4 b^{4})

Factor out

7 a^{4}

from

49 a^{8} + 14 a^{4} b^{2} : 7 a^{4} (7 a^{4} + 2 b^{2})

Factor out

2 b^{2}

from

14 a^{4} b^{2} + 4 b^{4} : 2 b^{2} (7 a^{4} + 2 b^{2})

= 7 a^{4} (7 a^{4} + 2 b^{2}) + 2 b^{2} (7 a^{4} + 2 b^{2})

Factor out common term

7 a^{4} + 2 b^{2}

= (7 a^{4} + 2 b^{2}) (7 a^{4} + 2 b^{2})

Apply exponent rule:

aa = a^{2}

(7 a^{4} + 2 b^{2}) (7 a^{4} + 2 b^{2}) = (7 a^{4} + 2 b^{2})^{2}

= (7 a^{4} + 2 b^{2})^{2}

(- 1) (2)

3^{3^{3^{3}}}

11 y z^{7} - 33 x^{4} y^{4} z^{3}

2 x \cdot 9

What is factor 49a^8+28a^4b^2+4b^4 ?
The solution to factor 49a^8+28a^4b^2+4b^4 is (7a^4+2b^2)^2