What is factor 2t^3-11t^2+12t+9 ?

The solution to factor 2t^3-11t^2+12t+9 is (2t+1)(t-3)^2

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factor 2t^3-11t^2+12t+9

factor

2 t^{3} - 11 t^{2} + 12 t + 9

(2 t + 1) (t - 3)^{2}

Solution steps

2 t^{3} - 11 t^{2} + 12 t + 9

Use the rational root theorem

= (2 t + 1) \frac{2 t ^{3} - 11 t ^{2} + 12 t + 9}{2 t + 1}

\frac{2 t ^{3} - 11 t ^{2} + 12 t + 9}{2 t + 1} = t^{2} - 6 t + 9

= (2 t + 1) (t^{2} - 6 t + 9)

Factor

t^{2} - 6 t + 9 : (t - 3) (t - 3)

= (2 t + 1) (t - 3) (t - 3)

Apply exponent rule:

aa = a^{2}

(t - 3) (t - 3) = (t - 3)^{2}

= (2 t + 1) (t - 3)^{2}

\frac{3 i ^{171} + 2}{4 i - i ^{20}}

\frac{36}{- 3}

\frac{24}{42} \frac{18}{42}

(2 + 5 i) (3 - 4 i)

3 (6 v + 3)

What is factor 2t^3-11t^2+12t+9 ?
The solution to factor 2t^3-11t^2+12t+9 is (2t+1)(t-3)^2