What is factor 2q^3-4q^2-8q+16 ?

The solution to factor 2q^3-4q^2-8q+16 is 2(q-2)^2(q+2)

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factor 2q^3-4q^2-8q+16

factor

2 q^{3} - 4 q^{2} - 8 q + 16

2 (q - 2)^{2} (q + 2)

Solution steps

2 q^{3} - 4 q^{2} - 8 q + 16

Factor out common term

2 : 2 (q^{3} - 2 q^{2} - 4 q + 8)

= 2 (q^{3} - 2 q^{2} - 4 q + 8)

Factor

q^{3} - 2 q^{2} - 4 q + 8 : (q - 2) (q + 2) (q - 2)

= 2 (q - 2) (q + 2) (q - 2)

Apply exponent rule:

aa = a^{2}

(q - 2) (q - 2) = (q - 2)^{2}

= 2 (q - 2)^{2} (q + 2)

\frac{1}{5} \cdot (- 10)

(1 + \frac{0.1}{360})^{360} - 1

\frac{( 3.01 ) ^{2} - 9}{( 3.01 ) - 3}

\frac{3}{8} \div \frac{2}{4}

- \frac{2}{3} + 7

What is factor 2q^3-4q^2-8q+16 ?
The solution to factor 2q^3-4q^2-8q+16 is 2(q-2)^2(q+2)