What is the answer to |((2y-7))/3 |=3 ?

The answer to |((2y-7))/3 |=3 is y=-1\lor y=8

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|((2y-7))/3 |=3

\frac{( 2 y - 7 )}{3} = 3

y = - 1 or y = 8

Solution steps

\frac{2 y - 7}{3} = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

\frac{2 y - 7}{3} = - 3 or \frac{2 y - 7}{3} = 3

\frac{2 y - 7}{3} = - 3 or \frac{2 y - 7}{3} = 3

y = - 1 or y = 8

2 x^{2} + 6 x - 2 = 5 x + 1

lo g_{16} (8) = x

x^{2} + 9 < x^{2} - 8

10 x - 50

2 x^{3} - x^{2} - 8 x + 4

What is the answer to |((2y-7))/3 |=3 ?
The answer to |((2y-7))/3 |=3 is y=-1\lor y=8
Solve for y: |((2y-7))/3 |=3
The solution is y=-1\lor y=8