What is (3x^{-4})^{-3}x^{-3} ?

The solution to (3x^{-4})^{-3}x^{-3} is (x^9)/(27)

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simplify (3x^{-4})^{-3}x^{-3}

simplify

(3 x^{- 4})^{- 3} x^{- 3}

\frac{x ^{9}}{27}

Solution steps

(3 x^{- 4})^{- 3} x^{- 3}

Simplify

(3 x^{- 4})^{- 3} : \frac{x ^{12}}{27}

= \frac{x ^{12}}{27} x^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 3} = \frac{1}{x ^{3}}

= \frac{x ^{12}}{27} \cdot \frac{1}{x ^{3}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{12} \cdot 1}{27 x ^{3}}

Apply rule:

a \cdot 1 = a

x^{12} \cdot 1 = x^{12}

= \frac{x ^{12}}{27 x ^{3}}

Simplify

\frac{x ^{12}}{x ^{3}} : x^{9}

= \frac{x ^{9}}{27}

\frac{2}{3} y - 2 (\frac{7}{3} y + z)

- (4 + m) + 2

\frac{x ^{2} - x y}{y - x}

(- 6) - (- 4)

6 \cdot 45

What is (3x^{-4})^{-3}x^{-3} ?
The solution to (3x^{-4})^{-3}x^{-3} is (x^9)/(27)