What are the solutions to the equation 5x^2+9=0 ?

The solutions to the equation 5x^2+9=0 are x= 3/(sqrt(5))i,x=-3/(sqrt(5))i

Find the zeros of 5x^2+9=0

The zeros of 5x^2+9=0 are x= 3/(sqrt(5))i,x=-3/(sqrt(5))i

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5 x^{2} + 9 = 0

x = \frac{3}{5} i, x = - \frac{3}{5} i

Solution steps

5 x^{2} + 9 = 0

Move

9

to the right side

5 x^{2} = - 9

Divide both sides by

5

x^{2} = - \frac{9}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{9}{5}, x = - - \frac{9}{5}

- \frac{9}{5} = \frac{3}{5} i

- - \frac{9}{5} = - \frac{3}{5} i

x = \frac{3}{5} i, x = - \frac{3}{5} i

2 r^{3} + 14 r^{2} - 36 r

\frac{15}{3 6}

9 - x < - 11

22 + \frac{5}{9} y = 7

y^{2} + 3 = 2 y

What are the solutions to the equation 5x^2+9=0 ?
The solutions to the equation 5x^2+9=0 are x= 3/(sqrt(5))i,x=-3/(sqrt(5))i
Find the zeros of 5x^2+9=0
The zeros of 5x^2+9=0 are x= 3/(sqrt(5))i,x=-3/(sqrt(5))i