What is log_{10}(42)+log_{10}(432) ?

The solution to log_{10}(42)+log_{10}(432) is log_{10}(18144)

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simplify log_{10}(42)+log_{10}(432)

simplify

lo g_{10} (42) + lo g_{10} (432)

lo g_{10} (18144)

Solution steps

lo g_{10} (42) + lo g_{10} (432)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (42) + lo g_{10} (432) = lo g_{10} (42 \cdot 432)

= lo g_{10} (42 \cdot 432)

Multiply the numbers:

42 \cdot 432 = 18144

= lo g_{10} (18144)

\frac{1}{( - 5.99 ) ^{2} - 36}

x^{2} + 23 x - 50

\frac{( x ^{2} + 15 - 8 x )}{( 3 - x )}

1 - 2

- 1 x^{1}

What is log_{10}(42)+log_{10}(432) ?
The solution to log_{10}(42)+log_{10}(432) is log_{10}(18144)