What is sqrt(60^2+40^2) ?

The solution to sqrt(60^2+40^2) is 20sqrt(13)

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simplify sqrt(60^2+40^2)

simplify

6 0^{2} + 4 0^{2}

2013

Decimal Notation

72.11102 \dots

Solution steps

6 0^{2} + 4 0^{2}

6 0^{2} + 4 0^{2} = 5200

= 5200

Prime factorization of

5200 : 2^{4} \cdot 5^{2} \cdot 13

= 2^{4} \cdot 5^{2} \cdot 13

2^{4} \cdot 5^{2} \cdot 13 = 2^{4} 5^{2} 13

= 2^{4} 5^{2} 13

2^{4} = 4

= 4 5^{2} 13

Apply radical rule:

a^{2} = a, a \geq 0

5^{2} = 5

= 4 \cdot 513

Multiply the numbers:

4 \cdot 5 = 20

= 2013

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