What is log_{28}(4)+log_{28}(7) ?

The solution to log_{28}(4)+log_{28}(7) is 1

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simplify log_{28}(4)+log_{28}(7)

simplify

lo g_{28} (4) + lo g_{28} (7)

1

Solution steps

lo g_{28} (4) + lo g_{28} (7)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{28} (4) + lo g_{28} (7) = lo g_{28} (4 \cdot 7)

= lo g_{28} (4 \cdot 7)

Multiply the numbers:

4 \cdot 7 = 28

= lo g_{28} (28)

Apply log rule:

lo g_{a} (a) = 1

= 1

\frac{x - 2}{x ^{2} - 4}

9 \cdot 1 0^{- 7}

\frac{7 π}{6} + π

(- 7 + 5 i) - (- 9 - 11 i)

x^{\frac{4}{2}}