What are the solutions to the equation x^2-8x-180=0 ?

The solutions to the equation x^2-8x-180=0 are x=18,x=-10

Find the zeros of x^2-8x-180=0

The zeros of x^2-8x-180=0 are x=18,x=-10

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x^{2} - 8 x - 180 = 0

x = 18, x = - 10

Solution steps

x^{2} - 8 x - 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 180 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 180) = 28

x_{1, 2} = \frac{- ( - 8 ) \pm 28}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 28}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 28}{2 \cdot 1}

x = \frac{- ( - 8 ) + 28}{2 \cdot 1} : 18

x = \frac{- ( - 8 ) - 28}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 18, x = - 10

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What are the solutions to the equation x^2-8x-180=0 ?
The solutions to the equation x^2-8x-180=0 are x=18,x=-10
Find the zeros of x^2-8x-180=0
The zeros of x^2-8x-180=0 are x=18,x=-10