What is (3a^5b^{-7})^{-3} ?

The solution to (3a^5b^{-7})^{-3} is (b^{21})/(27a^{15)}

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simplify (3a^5b^{-7})^{-3}

simplify

(3 a^{5} b^{- 7})^{- 3}

\frac{b ^{21}}{27 a ^{15}}

Solution steps

(3 a^{5} b^{- 7})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(3 a^{5} b^{- 7})^{- 3} = \frac{1}{( 3 a ^{5} b ^{- 7} ) ^{3}}

= \frac{1}{( 3 a ^{5} b ^{- 7} ) ^{3}}

Simplify

(3 a^{5} b^{- 7})^{3} : \frac{27 a ^{15}}{b ^{21}}

= \frac{1}{\frac{27 a ^{15}}{b ^{21}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{21}}{27 a ^{15}}

\frac{r}{3} - \frac{r}{2}

\frac{4 + 2 i}{( 4 + 2 i ) ( 3 + 5 i )}

2 (x^{2})^{2}

ln (0.000001)

a^{2} + \frac{1}{a ^{2}}

What is (3a^5b^{-7})^{-3} ?
The solution to (3a^5b^{-7})^{-3} is (b^{21})/(27a^{15)}