What is (n^2-9)/(n^2-6n+9) ?

The solution to (n^2-9)/(n^2-6n+9) is (n+3)/(n-3)

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simplify (n^2-9)/(n^2-6n+9)

simplify

\frac{n ^{2} - 9}{n ^{2} - 6 n + 9}

\frac{n + 3}{n - 3}

Solution steps

\frac{n ^{2} - 9}{n ^{2} - 6 n + 9}

Factor

n^{2} - 9 : (n + 3) (n - 3)

= \frac{( n + 3 ) ( n - 3 )}{n ^{2} - 6 n + 9}

Factor

n^{2} - 6 n + 9 : (n - 3)^{2}

= \frac{( n + 3 ) ( n - 3 )}{( n - 3 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(n - 3)^{2} = (n - 3) (n - 3)

= \frac{( n + 3 ) ( n - 3 )}{( n - 3 ) ( n - 3 )}

Cancel the common factor:

n - 3

= \frac{n + 3}{n - 3}

1 + (- \frac{3}{2})

(\frac{a}{2})^{2}

\frac{63}{90}

6 w^{2} + 11 w + 8 w^{2} - 15 w

8 \cdot 36