What is factor 1+125y^3 ?

The solution to factor 1+125y^3 is (5y+1)(25y^2-5y+1)

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factor 1+125y^3

factor

1 + 125 y^{3}

(5 y + 1) (25 y^{2} - 5 y + 1)

Solution steps

1 + 125 y^{3}

Write in the standard form

= 125 y^{3} + 1

Apply exponent rules

= (5 y)^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(5 y)^{3} + 1^{3} = (5 y + 1) (5^{2} y^{2} - 5 y + 1)

= (5 y + 1) (5^{2} y^{2} - 5 y + 1)

5^{2} = 25

= (5 y + 1) (25 y^{2} - 5 y + 1)

\frac{128}{5}

\frac{tan ( θ )}{1 - sec ^{2} ( θ )}

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(w^{2})^{5}